7.
D
H + 10.5
For example, for a decay rate... (Part C - page 4-6, para 4-7)
Time of burst was 0830, the first reading (Ta) was taken at 0900 (Ta = .5), the last
reading was at 1130 (Tb = 3).
Tp = 3(Tb Ta) + Tb
Tp = 3 x (3 .5) + 3
Tp = 3 x 2.5 + 3
Tp = 7.5 + 3
Tp = H + 10.5
Time of burst (Tp) = H + 10.5 or 1900 hours
8.
A
18
As a rule of thumb...time interval. (Part C - page 4-6, para 4-7)
4-17
CM2306
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